Perimeter of triangle

In the triangle, ABC angle A is 60° angle B is 90°, and side size c is 15 cm. Calculate the triangle circumference.

Correct answer:

o =  70.9808 cm

Step-by-step explanation:

$$\begin{gathered} c=15\text{ cm } \\ A=60^{\circ } \\ B=90^{\circ } \\ C=180-A-B=180-60-90=30^{\circ } \\ a=c\cdot \tan A^{\circ }=c\cdot \tan 60^{\circ }=15\cdot \tan 60^{\circ }=15\cdot 1.732051=25.98076\text{ cm } \\ b=\sqrt{a^2+c^2}=\sqrt{25.9808^2+15^2}=30\text{ cm } \\ o=a+b+c=25.9808+30+15=70.9808\text{ cm} \end{gathered}$$

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