Perimeter of triangle

In triangle ABC angle A is 60° angle B is 90° side size c is 15 cm. Calculate the triangle circumference.

Correct result:

o =  70.981 cm

Solution:

c=15 cm A=60 ∘ B=90 ∘ C=180−A−B=180−60−90=30 ∘ a=c⋅ tan⁡A∘=c⋅ tan⁡60∘ =15⋅ tan⁡60∘ =15⋅ 1.732051=25.98076 b=a2+c2=25.98082+152=30 cm o=a+b+c=25.9808+30+15=70.981 cmc=15 \ \text{cm} \ \\ A=60 \ ^\circ \ \\ B=90 \ ^\circ \ \\ C=180-A-B=180-60-90=30 \ ^\circ \ \\ a=c \cdot \ \tan A ^\circ =c \cdot \ \tan 60^\circ \ =15 \cdot \ \tan 60^\circ \ =15 \cdot \ 1.732051=25.98076 \ \\ b=\sqrt{ a^2+c^2 }=\sqrt{ 25.9808^2+15^2 }=30 \ \text{cm} \ \\ o=a+b+c=25.9808+30+15=70.981 \ \text{cm}

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