# Perimeter of triangle

In triangle ABC angle A is 60° angle B is 90° side size c is 15 cm. Calculate the triangle circumference.

Correct result:

o =  70.981 cm

#### Solution:

$c=15 \ \text{cm} \ \\ A=60 \ ^\circ \ \\ B=90 \ ^\circ \ \\ C=180-A-B=180-60-90=30 \ ^\circ \ \\ a=c \cdot \ \tan A ^\circ =c \cdot \ \tan 60^\circ \ =15 \cdot \ \tan 60^\circ \ =15 \cdot \ 1.732051=25.98076 \ \\ b=\sqrt{ a^2+c^2 }=\sqrt{ 25.9808^2+15^2 }=30 \ \text{cm} \ \\ o=a+b+c=25.9808+30+15=70.981 \ \text{cm}$

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