Perimeter of triangle

In triangle ABC angle A is 60° angle B is 90° side size c is 15 cm. Calculate the triangle circumference.

Result

o =  70.981 cm

Solution:

c=15 cm A=60 ∘ B=90 ∘ C=180−A−B=180−60−90=30 ∘ a=c⋅ tan⁡(A∘→rad)=c⋅ tan⁡(A∘⋅ π180 )=15⋅ tan⁡(60∘⋅ 3.1415926180 )=25.98076 b=a2+c2=25.98082+152=30 cm o=a+b+c=25.9808+30+15≐70.9808=70.981  cm c = 15 \ cm \ \\ A = 60 \ ^\circ \ \\ B = 90 \ ^\circ \ \\ C = 180-A-B = 180-60-90 = 30 \ ^\circ \ \\ a = c \cdot \ \tan( A ^\circ \rightarrow rad) = c \cdot \ \tan( A ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ ) = 15 \cdot \ \tan( 60 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ ) = 25.98076 \ \\ b = \sqrt{ a^2+c^2 } = \sqrt{ 25.9808^2+15^2 } = 30 \ cm \ \\ o = a+b+c = 25.9808+30+15 \doteq 70.9808 = 70.981 \ \text{ cm }

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