Warehouses

A company stored a total of 70 tonnes of grain across three warehouses. The second warehouse held 8.5 t less than the first, and the third held 3.5 t more than the first. How many tonnes of grain were stored in each warehouse?

Final Answer:

a =  25 t
b =  16.5 t
c =  28.5 t

Step-by-step explanation:


a+b+c=70
b = a - 8.5
c = a + 3.5

a+b+c = 70
a-b = 8.5
a-c = -3.5

Row 2 - Row 1 → Row 2
a+b+c = 70
-2b-c = -61.5
a-c = -3.5

Row 3 - Row 1 → Row 3
a+b+c = 70
-2b-c = -61.5
-b-2c = -73.5

Row 3 - -1/-2 · Row 2 → Row 3
a+b+c = 70
-2b-c = -61.5
-1.5c = -42.75


c = -42.75/-1.5 = 28.5
b = -61.5+c/-2 = -61.5+28.5/-2 = 16.5
a = 70-b-c = 70-16.5-28.5 = 25

a = 25
b = 33/2 = 16.5
c = 57/2 = 28.5

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algebraUnits of physical quantitiesGrade of the word problem

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