Accommodated 6906

Tourists are accommodated in three hotels. There are eight more tourists in the second hotel than in the first. In the third hotel are 14 more than in the second. How many tourists stayed in each hotel if there were 258 in total?

Correct answer:

a =  76
b =  84
c =  98

Step-by-step explanation:


b = 8 +a
c = 14+b
a+b+c = 258

a-b = -8
b-c = -14
a+b+c = 258

Row 3 - Row 1 → Row 3
a-b = -8
b-c = -14
2b+c = 266

Pivot: Row 2 ↔ Row 3
a-b = -8
2b+c = 266
b-c = -14

Row 3 - 1/2 · Row 2 → Row 3
a-b = -8
2b+c = 266
-1.5c = -147


c = -147/-1.5 = 98
b = 266-c/2 = 266-98/2 = 84
a = -8+b = -8+84 = 76

a = 76
b = 84
c = 98

Our linear equations calculator calculates it.



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