Rhomboid

Calculate the circumference and area of the rhomboid with sides 20 and 14, with their angle 50°.

Correct result:

S =  95.766
o =  68

Solution:

a=20 b=14 A=20∘→ rad=20∘⋅ π180 =20∘⋅ 3.1415926180 =0.34907=π/9  S=a⋅ b⋅ sin⁡(A)=20⋅ 14⋅ sin⁡(0.3491)=95.766a=20 \ \\ b=14 \ \\ A=20 ^\circ \rightarrow\ \text{rad}=20 ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ =20 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ =0.34907=π/9 \ \\ \ \\ S=a \cdot \ b \cdot \ \sin(A)=20 \cdot \ 14 \cdot \ \sin(0.3491)=95.766

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