#### Answer

$7.0\times10^{5}\,N$

#### Work Step by Step

Mass $m=2.0\times10^{5}\,kg$
Acceleration $a=3.5\,m/s^{2}$
$F_{net}=ma=2.0\times10^{5}\,kg\times3.5\,m/s^{2}=7.0\times10^{5}\,N$

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

$7.0\times10^{5}\,N$

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