Mass fraction

2 teaspoons (24 g) of sugar are dissolved in a cup with 500 g of tea. Calculate the weight fraction of sugar in the tea.

Correct answer:

f =  0.048

Step-by-step explanation:

$$\begin{gathered} m_1=500\text{ g } \\ {m}_2=24\text{ g } \\ f=m_2\mathrm{/}{m}_1=24\mathrm{/}500={\displaystyle \frac{6}{125}}=0.048 \end{gathered}$$

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