Contradiction 55571

Use the truth table to evaluate the truth of the compound statement
(a) [P ∧ (Q ∨ R)] ⇔ [(P ∧ Q) ∨ (P ∧ R)]
(b) ¬(P ⇒ ¬Q) ⇒ (¬P ∧ Q)
and decide each time whether it is a tautology or A contradiction.

Correct answer:

a =  1
b =  0

Step-by-step explanation:

a=1
P,Q,¬Q, P  ¬Q, X=¬(P  ¬Q), Y=¬P  Q, XY  0, 0,1 1,0,0,1  0, 1,0 1,0,1,1  1, 0,1,1,0,0,1  1, 1,0,0,1,0,0  b=0



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