Events

Event P has probability of 0.84. What is the probability that the event P occurs in 3, 5, 7 try.

Correct result:

x3 =  2.15 %
x5 =  0.06 %
x7 =  0 %

Solution:

p=0.84 q=1p=10.84=425=0.16   x3=100 q31 p=100 0.1631 0.84=1344625=1344625%=2.15%
 x5=100 q51 p=100 0.1651 0.84=0.06%
 x7=100 q71 p=100 0.1671 0.84=0%



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