Events

Event P has the probability of 0.84. What is the probability that the event P occurs in 3, 5, 7 try?

Correct answer:

x3 =  2.15 %
x5 =  0.06 %
x7 =  0 %

Step-by-step explanation:

p = 0.84 \ \\ q = 1 - p = 1 - 0.84 = \dfrac{ 4 }{ 25 } = 0.16 \ \\ \ \\ x3 = #%#p = 0.84 \ \\ q = 1 - p \ \\ \ \\ \ \\ x3 = 100 * pow(q, 3-1) * px_{3} = 100 \cdot \ q^{ 3-1 } \cdot \ p = 100 \cdot \ 0.16^{ 3-1 } \cdot \ 0.84 = 2.15 \%
x5 = #%# \ \\ x5 = 100 * pow(q, 5-1) * px_{5} = 100 \cdot \ q^{ 5-1 } \cdot \ p = 100 \cdot \ 0.16^{ 5-1 } \cdot \ 0.84 = 0.06 \%
x7 = #%# \ \\ x7 = 100 * pow(q, 7-1) * px_{7} = 100 \cdot \ q^{ 7-1 } \cdot \ p = 100 \cdot \ 0.16^{ 7-1 } \cdot \ 0.84 = 0 \%



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