Manganin

How long must a manganin wire with a diameter of 0.8 mm have a value of 10Ω?

Correct answer:

x =  10.472 m

Step-by-step explanation:

D=0.8 mm m=0.8:1000  m=0.0008 m R=10 Ω ρ=48 1084.8107 Ω  r=D/2=0.0008/2=25001=0.0004 m S=π r2=3.1416 0.000425.0265107 m2  R = ρ   x / S  x=S R/ρ=5.0265107 10/4.8107=10.472 m



Did you find an error or inaccuracy? Feel free to write us. Thank you!







You need to know the following knowledge to solve this word math problem:

    Units of physical quantities:

    Themes, topics:

    Grade of the word problem:


     
    We encourage you to watch this tutorial video on this math problem: video1

    Related math problems and questions: