# Profit per kilo

The trader sells apples at a profit of 20% per kilogram. Today, he decided to reduce the price of apples by 10%. How much profit does the trader have today?

Result

z =  8 %

#### Solution:

$p_{ 1 } = 1+20/100 = \dfrac{ 6 }{ 5 } = 1.2 \ \\ p_{ 2 } = p_{ 1 } - 10/100 \cdot \ p_{ 1 } = 1.2 - 10/100 \cdot \ 1.2 = \dfrac{ 27 }{ 25 } = 1.08 \ \\ z = 100 \cdot \ (p_{ 2 }-1) = 100 \cdot \ (1.08-1) = 8 = 8 \%$

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