# Profit per kilo

The trader sells apples at a profit of 20% per kilogram. Today, he decided to reduce the price of apples by 10%. How much profit does the trader have today?

Result

z =  8 %

#### Solution:

$p_{1}=1+20/100=\dfrac{ 6 }{ 5 }=1.2 \ \\ p_{2}=p_{1} - 10/100 \cdot \ p_{1}=1.2 - 10/100 \cdot \ 1.2=\dfrac{ 27 }{ 25 }=1.08 \ \\ z=100 \cdot \ (p_{2}-1)=100 \cdot \ (1.08-1)=8=8 \%$

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