Line - normal form

What is the equation of the line whose x-intercept is - 3 and y-intercept is -4? Find coefficients A, B, C in normal equation of line: Ax + By = C

Correct answer:

A =  4
B =  3
C =  -12

Step-by-step explanation:

U=(3,0) W=(0,4)  3 ...  prime number 4=22 LCM(3,4)=223=12  C=LCM(3,4)=12  A Ux+B Uy=C A Wx+B Wy=C A (3)+B 0=(12) A 0+B (4)=(12)  3A=12 4B=12  B=412=3 A=312=4  A=4 B=3  4x+3y=12 4x+3y+12=0



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Showing 1 comment:
Iknownobody
Hello, sir/ma'am! Good day. Since intercepts have been given, I used intercepts form which is x/a +y/b=1, doing operation eventually I got -1/3 x -1/4 y =12 so A=-⅓ B=-¼ and C= 12...





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