Investment

1000$is invested at 10% compound interest. What factor is the capital multiplied by each year? How much will be there after n=12 years? Correct result: f = 1.1 x = 3138.4284 USD Solution: $f=1+\frac{10}{100}=\frac{11}{10}=1.1$ We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you! Showing 0 comments: Tips to related online calculators Our percentage calculator will help you quickly calculate various typical tasks with percentages. You need to know the following knowledge to solve this word math problem: Next similar math problems: • Radioactive material A radioactive material loses 10% of its mass each year. What proportion will be left there after n=6 years? • Deposit If you deposit 719 euros the beginning of each year, how much money we have at 1.3% (compound) interest after 9 years? • Savings The depositor regularly wants to invest the same amount of money in the financial institution at the beginning of the year and wants to save 10,000 euros at the end of the tenth year. What amount should he deposit if the annual interest rate for the annua • Loan Apply for a$ 59000 loan, the loan repayment period is 8 years, the interest rate 7%. How much should I pay for every month (or every year if paid yearly). Example is for practise geometric progression and/or periodic payment for an annuity.
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