Investment

1000$ is invested at 10% compound interest. What factor is the capital multiplied by each year? How much will be there after n=12 years?

Correct result:

f =  1.1
x =  3138.4284 USD

Solution:

f=1+10100=1110=1.1
n=12  x=1000 fn=1000 1.112=3138.4284 USD



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