Divide

Divide area of rectangles with dimensions 32m and 10m by the ratio 7: 9. What area corresponds to a smaller section?

Result

S1 =  140 m2
S2 =  180 m2

Solution:

a=32 m b=10 m S=a⋅ b=32⋅ 10=320 m2  S1=S⋅ 77+9=320⋅ 77+9=140 m2a=32 \ \text{m} \ \\ b=10 \ \text{m} \ \\ S=a \cdot \ b=32 \cdot \ 10=320 \ \text{m}^2 \ \\ \ \\ S_{1}=S \cdot \ \dfrac{ 7 }{ 7+9 }=320 \cdot \ \dfrac{ 7 }{ 7+9 }=140 \ \text{m}^2
S2=S⋅ 97+9=320⋅ 97+9=180 m2S_{2}=S \cdot \ \dfrac{ 9 }{ 7+9 }=320 \cdot \ \dfrac{ 9 }{ 7+9 }=180 \ \text{m}^2

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