Truck

Truck went for 4 hours and 30 minutes. If truck increase speed by 11 km/h, went same distance in 2 hours.

Calculate this distance.

Result

s =  39.6 km

Solution:

t1=4+30/60=92=4.5 h t2=2 h   v t1=s (v+11) t2=s  v 4.5=s (v+11) 2=s  s4.5v=0 s2v=22  s=1985=39.6 =1985=39.6  km  v=445=8.8 t_{ 1 } = 4+30/60 = \dfrac{ 9 }{ 2 } = 4.5 \ h \ \\ t_{ 2 } = 2 \ h \ \\ \ \\ \ \\ v \cdot \ t_{ 1 } = s \ \\ (v+11) \cdot \ t_{ 2 } = s \ \\ \ \\ v \cdot \ 4.5 = s \ \\ (v+11) \cdot \ 2 = s \ \\ \ \\ s-4.5v = 0 \ \\ s-2v = 22 \ \\ \ \\ s = \dfrac{ 198 }{ 5 } = 39.6 \ \\ = \dfrac{ 198 }{ 5 } = 39.6 \ \text { km } \ \\ v = \dfrac{ 44 }{ 5 } = 8.8 \ \\







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