Find the 3

Find the distance and midpoint between A(1,2) and B(5,5).

Correct answer:

d =  5
x =  3
y =  3.5

Step-by-step explanation:

$$\begin{gathered} x_0=1 \\ {y}_0=2 \\ {x}_1=5 \\ {y}_1=5 \\ d=\sqrt{(x_1-x_0{)}^2+(y_1-y_0{)}^2}=\sqrt{(5-1{)}^2+(5-2{)}^2}=5 \end{gathered}$$

$x=(x_0+x_1)\mathrm{/}2=(1+5)\mathrm{/}2=3$

$y=(y_0+y_1)\mathrm{/}2=(2+5)\mathrm{/}2={\displaystyle \frac{7}{2}}=3\frac{1}{2}=3.5$

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