Ditch

Ditch profile is an isosceles trapezoid with bases of length 80m and 60m. The slope of the side wall of the ditch is 80°. Calculate the ditch depth.

Correct result:

h =  56.713 m

Solution:

a=80 m c=60 m x=(a−c)/2=(80−60)/2=10 m tan⁡80∘=h/x  h=x⋅ tan⁡80∘=tan⁡4π/9=56.713 ma=80 \ \text{m} \ \\ c=60 \ \text{m} \ \\ x=(a-c)/2=(80-60)/2=10 \ \text{m} \ \\ \tan 80^\circ =h/x \ \\ \ \\ h=x \cdot \ \tan 80 ^\circ =\tan 4π/9=56.713 \ \text{m}

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