The ditch

Ditch with cross section of an isosceles trapezoid with bases 2m 6m are deep 1.5m. How long is the slope of the ditch?

Result

x =  2.5 m

Solution:

x=1.52+((6−2)/2)2=52=2.5 mx=\sqrt{ 1.5^2+((6-2)/2)^2 }=\dfrac{ 5 }{ 2 }=2.5 \ \text{m}

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