Cross-section 46841

The cross-section of the channel has the shape of a trapezoid. The bottom width is 2.25 m, and the depth is 5 m. The walls have a slope of 68°12' and 73°45'. Calculate the upper channel width.

Correct answer:

a =  5.7072 m

Step-by-step explanation:

c=2.25 m h=5 m  α=686012=68+6012=6068 60+12=604080+12=604092=5341=68.2  β=736045=73+6045=6073 60+45=604380+45=604425=4295=73.75   tan α = h:a1 a1=h/tanα=h/tan68.2° =5/tan68.2° =5/2.500178=1.99986 m  tan β = h:a2 a2=h/tanβ=h/tan73.75° =5/tan73.75° =5/3.430845=1.45737 m  a=a1+c+a2=1.9999+2.25+1.45745.7072 m   Verifying Solution:  S=2a+c h=25.7072+2.25 519.8931 m2



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