Six-sided polygon

In a six-sided polygon. The first two angles are equal, the third angle is twice (the equal angles), two other angles are trice the equal angle, while the last angle is a right angle. Find the value of each angle.

Correct result:

A =  63
B =  63
C =  126
D =  189
F =  90
e =  189

Solution:


A=B
C = 2B
D = E
D = 3A
F = 90
A+B+C+D+E+F = (6-2) • 180

A=B
C = 2B
D = e
D = 3A
F = 90
A+B+C+D+e+F = (6-2) • 180

A-B = 0
2B-C = 0
D-e = 0
3A-D = 0
F = 90
A+B+C+D+F+e = 720

A = 63
B = 63
C = 126
D = 189
F = 90
e = 189

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