Building

How high is the building that throws horizontal shadow 85.6 m long at angle 34°12'?

Correct answer:

h =  58.17 m

Step-by-step explanation:

$$\begin{gathered} s=85.6\text{ m } \\ \alpha =34.2\text{ ° } \\ \tan \alpha =h:s \\ h=s\cdot \tan \alpha \mathrm{°}=s\cdot \tan 34.2\mathrm{°}=85.6\cdot \tan 34.2\mathrm{°}=85.6\cdot 0.679599=58.17=58.17\text{ m} \end{gathered}$$

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