Reflector

Circular reflector throws light cone with a vertex angle 49° and is on 33 m height tower. The axis of the light beam has with the axis of the tower angle 30°.

What is the maximum length of the illuminated horizontal plane?

Result

x =  43.09 m

Solution:

x=33⋅(tan⁡(30∘+49∘2)−tan⁡(30∘−49∘2))=43.09 mx = 33 \cdot ( \tan (30 ^\circ +\dfrac{ 49 ^\circ }2) - \tan(30 ^\circ -\dfrac{ 49 ^\circ }2) ) = 43.09 \ \text{m}

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