An oil

An oil drum is cut in half. One half is used as a water trough. Use the dimensions; length 82cm, width 56cm to estimate the capacity of the water trough in liters.

Result

V =  101 l

Solution:

l=82 cm=82/10 dm=8.2 dm w=56 cm=56/10 dm=5.6 dm  h=l/2=8.2/2=4110=4.1 dm r=w/2=5.6/2=145=2.8 dm  V=π⋅ r2⋅ h=3.1416⋅ 2.82⋅ 4.1≐100.9834=101  l l = 82 \ cm = 82 / 10 \ dm = 8.2 \ dm \ \\ w = 56 \ cm = 56 / 10 \ dm = 5.6 \ dm \ \\ \ \\ h = l/2 = 8.2/2 = \dfrac{ 41 }{ 10 } = 4.1 \ dm \ \\ r = w/2 = 5.6/2 = \dfrac{ 14 }{ 5 } = 2.8 \ dm \ \\ \ \\ V = \pi \cdot \ r^2 \cdot \ h = 3.1416 \cdot \ 2.8^2 \cdot \ 4.1 \doteq 100.9834 = 101 \ \text{ l }

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