Digits

Show that if x, y, z are 3 consecutive nonzero digits, zyx-xyz = 198, where zyx and xyz are three-digit numbers created from x, y, z.

Correct result:

a =  198

Solution:

a=zyxxyz a=100 (x+2)+10(x+1)+x(x 100+(x+1) 10+(x+2)) a=100x+200+10x+10+x100x10x10x2 a=200+10102=198



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