Ticket Sales Three Days

The museum sold seven thousand tickets in 3 days. We know that the second day sold 20% more tickets than the first day, and Day 3 sold 10% less than Day 2. How many tickets were sold on each day?

Final Answer:

a =  2134.1463
b =  2560.9756
c =  2304.878

Step-by-step explanation:


a+b+c=7000
b = 1.20 a
c = 0.90 b

a+b+c=7000
b = 1.20·a
c = 0.90·b

a+b+c = 7000
1.2a-b = 0
0.9b-c = 0

Pivot: Row 1 ↔ Row 2
1.2a-b = 0
a+b+c = 7000
0.9b-c = 0

Row 2 - 1/1.2 · Row 1 → Row 2
1.2a-b = 0
1.833b+c = 7000
0.9b-c = 0

Row 3 - 0.9/1.83333333 · Row 2 → Row 3
1.2a-b = 0
1.833b+c = 7000
-1.491c = -3436.364


c = -3436.36363636/-1.49090909 = 2304.87804878
b = 7000-c/1.83333333 = 7000-2304.87804878/1.83333333 = 2560.97560976
a = 0+b/1.2 = 0+2560.97560976/1.2 = 2134.14634146

a = 87500/41 ≈ 2134.146341
b = 2560.97561
c = 94500/41 ≈ 2304.878049

Our linear equations calculator calculates it.



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