A meter pole perpendicular to the ground throws a shadow of 40 cm long, the house throws a shadow 6 meters long. What is the height of the house?

Result

h2 =  15 m

Solution:

$t_{1}=40 \ cm=40 / 100 \ m=0.4 \ m \ \\ h_{1}=1 \ \text{m} \ \\ t_{2}=6 \ \text{m} \ \\ \ \\ h_{1}:t_{1}=h_{2}:t_{2} \ \\ h_{2}=h_{1} \cdot \ \dfrac{ t_{2} }{ t_{1} }=1 \cdot \ \dfrac{ 6 }{ 0.4 }=15 \ \text{m}$

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