Shadow

A meter pole perpendicular to the ground throws a shadow of 40 cm long, the house throws a shadow 6 meters long. What is the height of the house?

Correct result:

h₂ =  15 m

Solution:

$$\begin{gathered} t_1=40\text{ cm}\to \text{ m}=40\mathrm{/}100\text{ m}=0.4\text{ m } \\ {h}_1=1\text{ m } \\ {t}_2=6\text{ m } \\ {h}_1:t_1=h_2:t_2 \\ {h}_2=h_1\cdot {\displaystyle \frac{t_2}{t_1}}=1\cdot {\displaystyle \frac{6}{0.4}}=15\text{ m} \end{gathered}$$

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