Two masters

The two masters will make as many parts as five apprentices at the same time. An eight-hour shift begins at 6 o'clock. When can a master finish the job to produce just as much as an apprentice for the whole shift?

Result

t = 9:12 hh:mm

Solution:

$$\begin{gathered} u=8\text{ h } \\ 5m=2u \\ m=2\cdot u\mathrm{/}5=2\cdot 8\mathrm{/}5={\displaystyle \frac{16}{5}}=3.2\text{ h } \\ t=6.00+m=6.00+3.2={\displaystyle \frac{46}{5}}=9.2=9:12\text{ hh}:\text{mm} \end{gathered}$$

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