Two masters

The two masters will make as many parts as five apprentices at the same time. An eight-hour shift begins at 6 o'clock. When can a master finish the job to produce just as much as an apprentice for the whole shift?

Result

t = 9:12 hh:mm

Solution:

$u=8 \ \text{h} \ \\ 5m=2u \ \\ m=2 \cdot \ u/5=2 \cdot \ 8/5=\dfrac{ 16 }{ 5 }=3.2 \ \text{h} \ \\ \ \\ t=6.00 + m=6.00 + 3.2=\dfrac{ 46 }{ 5 }=9.2=9:12 \ \text{hh}:\text{mm}$

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