Jose and Kaitlyn

Jose and Kaitlyn have a contest to see who can throw a baseball the farthest. Kaitlyn wins with a throw of 200 ft. If Jose threw the ball 3/4 as far as Kaitlyn, how far did Jose throw the ball?

Correct answer:

x =  150 ft

Step-by-step explanation:

$$\begin{gathered} K=200\text{ft} \\ x=K\cdot \frac{3}{4}=200\cdot \frac{3}{4}=\frac{200\cdot 3}{4}=\frac{600}{4}=150\text{ft} \end{gathered}$$

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