Jose and Kaitlyn

Jose and Kaitlyn have a contest to see who can throw a baseball the farthest. Kaitlyn wins, with a throw of 200 ft. If Jose threw the ball 3/4 as far as Kaitlyn, how far did Jose throw the ball?

Correct result:

x =  150 ft

Solution:

$x=200\cdot {\displaystyle \frac{3}{4}}=150\text{ ft}$

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