# Spruce height

How tall was spruce that was cut at an altitude of 8m above the ground and the top landed at a distance of 15m from the heel of the tree?

Result

x =  25 m

#### Solution:

$a=8 \ \text{m} \ \\ b=15 \ \text{m} \ \\ \ \\ \ \\ c=\sqrt{ a^2+b^2 }=\sqrt{ 8^2+15^2 }=17 \ \text{m} \ \\ \ \\ x=a+c=8+17=25 \ \text{m}$

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