Broken tree

The tree was 35 meters high. The tree broke at a height of 10 m above the ground. Top but does not fall off it refuted on the ground. How far from the base of the tree lay its peak?

Correct result:

x =  22.9129 m

Solution:

$$\begin{gathered} s=35\text{ m } \\ z=10\text{ m } \\ {x}^2+z^2=(s-z{)}^2 \\ x=\sqrt{(s-z{)}^2-z^2}=\sqrt{(35-10{)}^2-10^2}=5\sqrt{21}=22.9129\text{ m} \end{gathered}$$

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