Broken tree

The tree was 35 meters high. The tree broke at a height of 10 m above the ground. Top but does not fall off it refuted on the ground. How far from the base of the tree lay its peak?

Correct result:

x =  22.913 m

Solution:

s=35 m z=10 m  x2+z2=(s−z)2  x=(s−z)2−z2=(35−10)2−102=5 21=22.913 ms=35 \ \text{m} \ \\ z=10 \ \text{m} \ \\ \ \\ x^2 + z^2=(s-z)^2 \ \\ \ \\ x=\sqrt{ (s-z)^2-z^2 }=\sqrt{ (35-10)^2-10^2 }=5 \ \sqrt{ 21 }=22.913 \ \text{m}

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