# Vinegar mixing

We mix 70g water and 50g 8% vinegar. How many percents of the solution of vinegar we produce?

Result

p =  3.333 %

#### Solution:

$m_{1}=70 \ \text{g} \ \\ m_{2}=50 \ \text{g} \ \\ \ \\ v=0.08 \cdot \ m_{2}=0.08 \cdot \ 50=4 \ \text{g} \ \\ \ \\ p=100 \cdot \ \dfrac{ v }{ m_{1}+m_{2} }=100 \cdot \ \dfrac{ 4 }{ 70+50 } \doteq \dfrac{ 10 }{ 3 } \doteq 3.3333 \doteq 3.333 \%$

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