Vinegar

What percentage vinegar we get if we mix 1 if dm³ eight percent vinegar with 1.5 dm³ six percent vinegar?

Correct result:

x =  6.8 %

Solution:

$x={\displaystyle \frac{1\cdot 8+1.5\cdot 6}{1+1.5}}={\displaystyle \frac{34}{5}}={\displaystyle \frac{34}{5}}\mathrm{\%}=6.8\mathrm{\%}$

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