A triangle 4

A triangle has a perimeter of 18a + 6b + 15 and has sides of lengths 5a + 7 and 8a +4b. What is the length of the third side? Write an expression and simplify it to find the solution to the problem.

Correct answer:

Z = 5 a + 2 b + 8

Step-by-step explanation:

p= 18a + 6b + 15 X = 5a+7 Y=8a +4b  p=X+Y+Z Z = pXY Z = 18a + 6b + 15  ( 5a+7)  (8a +4b)  Z=5 a+2 b+8



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