# Possible lengths

Find the most possible lengths for the third side of a triangle with sides 20 and 18.

Result

c = (Correct answer is: 2 < c < 38)

#### Solution:

$a = 20 \ \\ b = 18 \ \\ \ \\ a+b > c \ \\ a+c > b \ \\ b+c > a \ \\ \ \\ 20+18 >c \ \\ 20+c >18 \ \\ 18+c >20 \ \\ \ \\ 38 > c \ \\ -2

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