Triangle perimeter

Calculate the triangle perimeter whose sides are in ratio 3: 5: 7 and the longest side is 17.5 cm long.

Correct result:

o =  37.5 cm

Solution:

$$\begin{gathered} c=17.5\text{ cm } \\ x=c\mathrm{/}7=17.5\mathrm{/}7={\displaystyle \frac{5}{2}}=2\frac{1}{2}=2.5\text{ cm } \\ o=(3+5+7)\cdot x=(3+5+7)\cdot 2.5={\displaystyle \frac{75}{2}}=37\frac{1}{2}={\displaystyle \frac{75}{2}}\text{ cm}=37.5\text{ cm} \end{gathered}$$

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