Diameter of a cylinder

The diameter of the cylinder is 42 cm. How many times does the cylinder turn on a 66m long track?

Result

n =  50

Solution:

D=42 cm=42/100 m=0.42 m s=66 m  o=π⋅ D=3.1416⋅ 0.42≐1.3195 m  n=s/o=66/1.3195≐50.0201≐50D=42 \ cm=42 / 100 \ m=0.42 \ m \ \\ s=66 \ \text{m} \ \\ \ \\ o=\pi \cdot \ D=3.1416 \cdot \ 0.42 \doteq 1.3195 \ \text{m} \ \\ \ \\ n=s/o=66/1.3195 \doteq 50.0201 \doteq 50

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