Internet anywhere

In school, 60% of pupils have access to the internet at home. A group of 8 students is chosen at random. Find the probability that
a) exactly 5 have access to the internet.
b) At least 6 students have access to the internet

Correct result:

a =  0.2787
b =  0.3154

Solution:

C5(8)=(85)=8!5!(85)!=876321=56 p=60/100=35=0.6 q=1p=10.6=25=0.4  a=(58) p5 q85=(58) 0.65 0.485=0.2787
C6(8)=(86)=8!6!(86)!=8721=28 C7(8)=(87)=8!7!(87)!=81=8 C8(8)=(88)=8!8!(88)!=11=1  p6=(68) p6 q86=(68) 0.66 0.4860.209 p7=(78) p7 q87=(78) 0.67 0.4870.0896 p8=(88) p8 q88=1 0.68 0.4880.0168  b=p6+p7+p8=0.209+0.0896+0.0168=0.3154



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