# Three-digit integers

How many three-digit natural numbers exist that do not contain zero and are divisible by five?

Correct result:

n =  81

#### Solution:

$n=9 \cdot \ 9 \cdot \ 1=81$ We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you! Tips to related online calculators
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