Perpendicular 80464

A group of tourists split up at the intersection of two perpendicular paths. One group walked at a speed of 5.3 km/h. Second group 4.1km/h. How far were the two groups from each other after 1h 25min?

Correct answer:

x =  9.4927 km

Step-by-step explanation:

v1=5.3 km/h v2=4.1 km/h  t=1:25=1 hr 25 min =1+6025=1.4167 hr1.4167  s1=v1 t=5.3 1.4167=1209017.5083 km s2=v2 t=4.1 1.4167=1206975.8083 km  x2 = s12 + s22  x=s12+s22=7.50832+5.80832=9.4927 km



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