Joe had

Joe had a full tank of petrol in his car. His car consumed 2/9 of the tank of petrol on Saturday and 1/3 of it on Sunday. What fraction of the tank of petrol was left after the weekend?

Correct answer:

x =  4/9

Step-by-step explanation:

$$\begin{gathered} s=\frac{2}{9}+\frac{1}{3}=\frac{2}{9}+\frac{3}{9}=\frac{2+3}{9}=\frac{5}{9}\doteq 0.5556 \\ x=1-s=1-\frac{5}{9}=\frac{1\cdot 9}{9}-\frac{5}{9}=\frac{9}{9}-\frac{5}{9}=\frac{9-5}{9}=\frac{4}{9}=0.4444 \end{gathered}$$

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