A+B+C=one hundred

A+B+C=100. If A=27.5 and the value of B are between 10 and 15 and which has two decimal places, then what can be the greatest value of C?

Correct answer:

C =  62.49

Step-by-step explanation:

A=27.5 A+B+C=100 B+C = 100  27.5 = 72.5 10<B<15 B=XX.01 B=10.01  C=72.5B=72.510.01=1006249=6210049=62.49   Verifying Solution:   s=A+B+C=27.5+10.01+62.49=100

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