Carpenters

Carpenters 1 and 2 spend 10 days and 5 days respectively to make one table. If 50 tables were made by the first carpenter and 30 tables were made by the second carpenter, What is the average time spent on the products?

Correct result:

t =  8.125 d

Solution:

$t={\displaystyle \frac{10\cdot 50+5\cdot 30}{50+30}}={\displaystyle \frac{65}{8}}=8{\displaystyle \frac{1}{8}}={\displaystyle \frac{65}{8}}\text{ d}=8.125\text{ d}$

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