A train 6
A train covers distances of 10 km, 20 km, and 30 km at speeds of 50 km/h, 60 km/h, and 90 km/h respectively. Find the average speed of the train in km/h.
Final Answer:
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Dr. Math
1. For the first segment: 10 km at 50 km/h.
Time = Distance / Speed = 10 / 50 hours.
2. Second segment: 20 km at 60 km/h.
Time = 20 / 60 hours.
3. Third segment: 30 km at 90 km/h.
Time = 30 / 90 hours.
Now, I'll calculate each time:
1. First part: 10/50 = 0.2 hours.
2. Second part: 20/60 ≈ 0.333... hours.
3. Third part: 30/90 = 1/3 ≈ 0.333... hours.
Adding these up for total time:
Total Time = 0.2 + 0.333... + 0.333...
Which is approximately 0.8667 hours.
The total distance is 10 + 20 + 30 = 60 km.
So average speed = Total Distance / Total Time
= 60 / 0.8667 ≈ 69.23 km/h.
Time = Distance / Speed = 10 / 50 hours.
2. Second segment: 20 km at 60 km/h.
Time = 20 / 60 hours.
3. Third segment: 30 km at 90 km/h.
Time = 30 / 90 hours.
Now, I'll calculate each time:
1. First part: 10/50 = 0.2 hours.
2. Second part: 20/60 ≈ 0.333... hours.
3. Third part: 30/90 = 1/3 ≈ 0.333... hours.
Adding these up for total time:
Total Time = 0.2 + 0.333... + 0.333...
Which is approximately 0.8667 hours.
The total distance is 10 + 20 + 30 = 60 km.
So average speed = Total Distance / Total Time
= 60 / 0.8667 ≈ 69.23 km/h.
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