Mr.de

Mr. Guzman bought 7 1/2 kg of meat. He used 2 3/4 kg for afritada, 3 1/8 kg for menudo, and the rest for pochero. How many kilograms of meat did he use for pochero?

Final Answer:

x =  1 ⁵⁄₈ = 13/8 kg

Step-by-step explanation:

$$\begin{gathered} m=7\frac{1}{2}=7+\frac{1}{2}=\frac{7\cdot 2+1}{2}=\frac{14+1}{2}=\frac{15}{2}=7.5\text{kg} \\ a=2\frac{3}{4}=2+\frac{3}{4}=\frac{2\cdot 4+3}{4}=\frac{8+3}{4}=\frac{11}{4}=2.75\text{kg} \\ b=3\frac{1}{8}=3+\frac{1}{8}=\frac{3\cdot 8+1}{8}=\frac{24+1}{8}=\frac{25}{8}=3.125\text{kg} \\ x=m-a-b=\frac{15}{2}-\frac{11}{4}-\frac{25}{8}=\frac{60}{8}-\frac{22}{8}-\frac{25}{8}=\frac{60-22-25}{8}=\frac{13}{8}=\frac{13}{8}\text{kg}=1\frac{5}{8}\text{kg}=1.625\text{kg} \end{gathered}$$

Try another example