Assume 2

Assume you are working with a standard six-sided die.

What is the probability of rolling the die once and obtaining a 5 and then rolling the die again and obtaining a 2? (input 3 numbers after the decimal, do not round). Report probability as a proportion.

Correct answer:

p =  1/36

Step-by-step explanation:

$$\begin{gathered} p_1=\frac{1}{6}\doteq 0.1667 \\ p=p_1\cdot p_1=\frac{1}{6}\cdot \frac{1}{6}=\frac{1\cdot 1}{6\cdot 6}=\frac{1}{36}=0.0278 \end{gathered}$$

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