Competition 81952

All three team members took turns fulfilling the competition task without delay. The first member used up 30% of the total competition time. The second needed 10 minutes more than the first, and only 10 minutes remained for the third. What % of the total time did the other member need?

Correct answer:

p2 =  50 %

Step-by-step explanation:

p1=30%=10030=103=0.3 b= 10  + a c=10 min  a = p1   (a+b+c)  a=p1 (a+(10+a)+c) a=0.3 (a+(10+a)+10)  0.4a=6  a=0.46=15  a=15  a=15 min b=10+a=10+15=25 min  s=a+b+c=15+25+10=50 min  p2=100 sb=100 5025=50100 25=502500=50%



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