HCF of polynoms

Find the HCF of the given expression: 2a2b2c4, 2a4b3c3 and 4a2b3

Correct answer:

f = 2a^2b^2

Step-by-step explanation:

x=2a2b2c4 y=2a4b3c3 z=4a2b3  f = 2 a2 b2 c0 f=2a2b2

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