Aquaristics

We consider 'words' (i.e., arbitrary strings of letters) obtained by rearranging the letters of the word 'AQUARISTICS'. All letters are treated as distinguishable from each other. The number of such words that also contain the string 'CAVA' (as consecutive letters in the given order) is equal to:
(A) 11!/4!
(B) 4! · 7!
(C) 8! · 3! · 2!
(D) 11!/(3! · 2! · 2!)

Final Answer:

x = D

Step-by-step explanation:

n=11 n(K)=2 n(A)=3 n(V)=1  x=D



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