Word OPTICAL
Find the number of possible different arrangements of the letters of the word OPTICAL such that the vowels would always be together.
Final Answer:
Showing 1 comment:
Polda24
the word OPTICAL has three vowels and 4 consonants. Since all the three vowels are to be together, mark as one symbol X This with the 4 consonants become 5 which can be permuted in 5! = 120 ways. The three vowels in X can be permuted among themselves in 3! = 6 ways.
The total number of arrangements of the letters of the word OPTICAL so that all the vowels are always together is 120 x 6 = 720.
The total number of arrangements of the letters of the word OPTICAL so that all the vowels are always together is 120 x 6 = 720.
3 years ago 1 Like
Tips for related online calculators
You need to know the following knowledge to solve this word math problem:
combinatoricsbasic operations and conceptsGrade of the word problem
Related math problems and questions:
- Round table
Find the number of ways in which eight people can be seated at a round table such that 2 of them always sit together. - Class arrangements
There are 4 classrooms on the ground floor of the school building, which are numbered 1,2,3,4. First-year students A, B, C, and D will be placed in these classrooms. Write all possible class arrangements and their number. Thank you - Twelve flowers
A florist has roses, tulips, daffodils, and carnations to use in flower arrangements. If she were to make an arrangement using 12 flowers, how many different combinations of these four types of flowers would be possible? - Forest herb leaves
Only herbs with 5 and 7 leaves grow in the Old Forest. When the boar Vavřínec collects raw materials for herbal liquor, it always tears off the whole herb and puts it in a basket. What is the most significant number of letters he will ever manage to have - Element arrangement ways
Determine the number of arrangements of these six elements: a, a, a, b, b, c. - Letter puzzle
Find out what numbers need to be substituted for the letters X, Y, and Z to have the following relation: XZY + XYZ --------- YZX - School group
There are five girls and seven boys in the group. They sit in a row next to each other. How many options if no two girls sit next to each other?
