Reminder and quotient

There are given the number C = 281, D = 201. Find the highest natural number S so that the C:S, D:S are with the remainder of 1,

Correct result:

S =  40

Solution:

C=281 D=201  C1=C−1=281−1=280 D1=D−1=201−1=200  280=23⋅5⋅7 200=23⋅52 GCD(280,200)=23⋅5=40  S=GCD(C1,D1)=GCD(280,200)=40

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