Resistance 82533

A current of 275 mA passes through the filament of a light bulb with a resistance of 800 Ω. What voltage is the bulb connected to?

Correct answer:

U =  220 V

Step-by-step explanation:

R=800 Ω I=275 mA A=275:1000  A=0.275 A  I = RU U=R I=800 0.275=220 V



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