Filament of bulb

The filament of bulb has a 1 ohm resistivity and is connected to a voltage 220 V. How much electric charge will pass through the fiber when the electric current passes for 10 seconds?

Correct result:

Q =  2200 C

Solution:

U=220 V R=1 Ohm I=U/R=220/1=220 A t=10 s I=Q/t Q=I t=220 10=2200 C



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