Filament of bulb

The filament of bulb has a 1 ohm resistivity and is connected to a voltage 220 V. How much electric charge will pass through the fiber when the electric current passes for 10 seconds?

Correct result:

Q =  2200 C

Solution:

$$\begin{gathered} U=220\text{ V } \\ R=1\text{ Ohm } \\ I=U\mathrm{/}R=220\mathrm{/}1=220\text{ A } \\ t=10\text{ s } \\ I=Q\mathrm{/}t \\ Q=I\cdot t=220\cdot 10=2200\text{ C} \end{gathered}$$

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